Why is the product of $ceAl(OH)3 + NaOH -> Na$ và not $ceNaAlO3H2 + H2O$? Is this an acid-base reaction?


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All reaction sources: Chemiday

As I said in the bình luận section that aluminium hydroxide is amphoteric i.e. It dissolves in acid, forming $ce^3+$ (hexaaquaaluminium) or its hydrolysis products & dissolves in strong alkaline solutions, forming $ce−$ (tetrahydroxidoaluminate). So, when it is dissolved in base, it forms a sodium aluminohydroxo complex salt. Why? Because as
Pritt mentioned, aluminium has vacant orbital for which miễn phí electron can reside there forming a complex salt.

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$$ceAl(OH)3 + NaOH(conc.) → Na$$

$$ceAl(OH)3 + 3NaOH → Na3$$

No worries. There is also an acid-base reaction where the two combines to form a salt và water but this occurs at very high temperature và you won"t find this type of reaction occurring in laboratory. This reaction can only be find in industries.

$$ceAl(OH)3 + NaOH -><1000 C> NaAlO2 + 2H2O$$

If only aluminium was used, there would be evolution of hydrogen gas from a very similar exothermic reaction. Lưu ý for simplicity, the species is written $ceNaAlO2$ but it actually contains $ce−$ ion or perhaps the $ce−$ all due to lớn presence of vacant orbital(see sodium aluminate).


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answered Jun 19, 2017 at 5:27
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Nilay GhoshNilay Ghosh
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