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note that if you solve e^y=2 you get y=ln(2). This tells us that 2=e^ln(2) which you probably already know. Now we can solve this equation two ways: Method 1 : as you solved it. 2^x=129 Rightarrow x =log_2(129) ,. ...
2x=5122 to lớn the power nguồn of x equals 512Take the log of both sides log10(2x)=log10(512) Rewrite the left side of the equation using the rule for the log of a power x•log10(2)=log10(512) Isolate the ...
We have, 2^x=100 Taking log on both the sides Log2^x=log(100) Since logx^y=ylogx Therefore, xlog2=log100 Value of log2=0.693 và log100=4.605 Putting the values we get x(0.693)=4.605 ...
There is no pure algebraic solution using elementary functions, but there is an effective numerical method.Explanation:Given: displaystyle2^x=10x Define: displaystylefleft(x ight)=2^x-10x ...
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2x=1312 lớn the power nguồn of x equals 131Take the log of both sides log10(2x)=log10(131) Rewrite the left side of the equation using the rule for the log of a power x•log10(2)=log10(131) Isolate the ...
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left< eginarray l l 2 và 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 và 3 \ -1 và 1 & 5 endarray ight>
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